HomeMock TestMHADA Exam Civil Technical IMP Question Mock Test 55 MHADA Exam Civil Technical IMP Question Mock Test 55 Prashik November 17, 2021 0 1➤ An R.C.C. beam of 6 m span is 30 cm wide and has a lever arm of 55 cm. If it carries a U.D.L. of 12 t per m and allowable shear stress is 5 kg/cm2, the beamIs safe in shearIs safe with stirrups and inclined barsIs safe with stirrupsNeeds revision of section 2➤ According to I.S. : 456, slabs which span in two directions with corners held down, are assumed to be divided in each direction into middle strips and edge strips such that the width of the middle strip, isHalf of the width of the slabTwo -third of the width of the slabThree-fourth of the width of the slabFour-fifth of the width of the slab 3➤ The load stress of a section can be reduced byDecreasing the lever armIncreasing the total perimeter of barsReplacing larger bars by greater number of small barsReplacing smaller bars by greater number of greater bars 4➤ the column head support a flat slab, is generally kept The diameter of0.25 times the span length0.25 times the diameter of the column4.0 cm larger than the diameter of the column5.0 cm larger than the diameter of the column 5➤ fixed at its ends, the If is the uniformly distributed load on a circular slab of radius maximum positive radial moment at its centre, is3WR²/162WR²/16WR²/16None of these 6➤ The maximum ratio of span to depth of a slab simply supported and spanning in one direction, is35253020 7➤ If the width of the foundation for two equal columns is restricted, the shape of the footing generally adopted, isSquareRectangularTrapezoidalTriangular 8➤ The floor slab of a building is supported on reinforced cement floor beams. The ratio of the end and intermediate spans is kept0.70.80.90.6 9➤ Pick up the correct statement from the following:Lateral reinforcement in R.C.C. columns is provided to prevent the longitudinal reinforcement from bucklingLateral reinforcement prevents the shearing of concrete on diagonal planeLateral reinforcement stops breaking away of concrete cover, due to bucklingAll the above 10➤ In case the factor of safety against sliding is less than 1.5, a portion of slab is constructed downwards at the end of the heel slab, which is known asA keyA cut-off wallA ribAll the above 11➤ Lapped splices in tensile reinforcement are generally not used for bars of size larger than18 mm diameter24 mm diameter30 mm diameter36 mm diameter 12➤ Minimum spacing between horizontal parallel reinforcement of the same size should not be less thanOne diameter2.5 diameters3 diameters3.5 diameters 13➤ For a ribbed slabClear spacing between ribs shall not be greater than 4.5 cmOverall depth of the slab shall not exceed four times the breadth of the ribWidth of the rib shall not be less than 7.5 cmAll the above 14➤ A very comfortable type of stairs isStraightGeometricalDog leggedOpen newel 15➤ Columns may be made of plain concrete if their unsupported lengths do not exceed their least lateral dimensionTwo timesThree timesFour timesFive times 16➤ The width of the flange of a L-beam, should be less thanOne- sixth of the effective spanBreadth of the rib + four times thickness of the slabBreadth of the rib + half clear distance between ribsLeast of the above 17➤ A pre-stressed concrete member is preferred becauseIts dimensions are not decided from the diagonal tensile stressRemoval of cracks in the members due to shrinkageLarge size of long beams carrying large shear force need not be adoptedAll the above 18➤ If the ratio of the span to the overall depth does not exceed 10, the stiffness of the beam will ordinarily be satisfactory in case of aSimply supported beamContinuous beamCantilever beamNone of these 19➤ carrying a uniformly distributed load per metre length is suspended at two A pile of length points, the maximum, B.M. at the centre of the pile or at the points of suspension, isWL/8WL²/47WL²/24WL²/16 20➤ If is the net upward pressure on a square footing of side for a square column of side , the maximum bending moment is given byB.M = pb (c – a)/4B.M = pb (b – a)²/4B.M = pb (b – a)²/8B.M = pb (b + a)/8 SubmitYour score is Tags Mock Test Newer Older